WebMay 29, 2024 · Scanner input = new Scanner (System.in); int k = input.nextInt (); int total = 0; int count = 0; while (count != k && input.hasNext ()) { count++; total += input.nextInt (); } System.out.println (total); This will get only one line. To get more lines try my program above. And read this to learn more about hasnext (). Share Follow WebAug 20, 2016 · When switching between reading tokens of input and reading a full line of input, you need to make another call to nextLine () because the Scanner object will read the rest of the line where its previous read left off. If there is nothing on the line, it simply consumes the newline and moves to the beginning of the next line.
Java User Input and Scanner Class: A Step-By-Step Guide
Web1. Using Two Scanners The idea is to use two scanners – one to get each line using Scanner.nextLine (), and the other to scan through it using Scanner.next (). Download … WebJul 29, 2016 · Since You know the number of rows, use for loop to iterate that number of rows and then use scanner.nextLine to get a row. Create a method maybe called parseIntFromString (). You can then use the extensive String manipulations to get the integers and add them together. I have added an example to get you started: halloween virtual background for teams
Java scanner count lines in file - Stack Overflow
WebApr 11, 2024 · Industrial CT is useful for defect detection, dimensional inspection and geometric analysis, while it does not meet the needs of industrial mass production because of its time-consuming imaging procedure. This article proposes a novel stationary real-time CT system, which is able to refresh the CT-reconstructed slices to the detector frame … WebMay 5, 2024 · Scanner in = new Scanner (str) ; in.useDelimiter (":") ; ArrayList al = new ArrayList<> () ; while ( in.hasNext ()) { al.add (in.next () ) ; } for ( int i = 0 ; i < al.size (); ++i ) { String s = al.get (i) ; String [] s2 = s.split (",") ; System.out.println ( s2 [0] ); } Share Follow edited May 5, 2024 at 2:31 WebApr 4, 2015 · Scanner inputLine; Scanner inputToken; try { int counter = 1; inputLine = new Scanner (new File ("a.txt")); while (inputLine.hasNextLine ()) { inputToken=new Scanner (inputLine.nextLine ()); while (inputToken.hasNext ()) { String x = inputToken.next (); x = x.replaceAll (" [^a-zA-Z\\s]", "").replaceAll ("\\s+", " "); if (!dictionary.contains (x)) … halloween vocabulary for kids pdf